if x is less than y

Getting Started
1

a variable X (text input field) will be between 1-9
or it will be between 10-16

if X is 1-9 (or less than 10 however you want to say it)
then I need to make Y (a string) “00”

if X is 10-16
then I need to make Y “0”

how do I do this.
thanks for any help

2

Use an if statement like

if x >0 and x<10 then mystring = "00" end if

3

Do you want

TheString = format(x,“000”)

so that all the numbers end up as 3 digits?

4

michel cool will this work

[code]if x >0 and x<10 then
mystring = “00”
else
mystring = “0”
end if

[/code]

5

a variable X (text input field) will be between 1-9

so you don’t need if x >0

6

[quote=225893:@Jeff Tullin]a variable X (text input field) will be between 1-9

so you don’t need if x >0[/quote]

Unless additional data validation on input, count on the universe to have an idiot throw sand in the gears…

7

here is what I wrote, does not work
says mystring does not exist

[code] If ComboBox1.text = “AXS- Access Promos” then

if TextField_CD.Text  < "10" then
  Dim mystring as string = "00"
else
  Dim mystring as string = "0"
end


MsgBox  field + mystring + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text[/code]
8

do I need to convert the 10 to an integer NOT a string

9 
dim Y as string
if bin(x).Len > 3 then Y = "0" else Y = "00"

:wink:

10

or shorter:

dim Y as string Y = "0" + If(bin(x).Len > 3),"0","")

not tested in IDE…

11

error says mystring does not exist

if bin(TextField_CD.Text).Len > 3 then mystring = "0" else mystring = "00"

12

Shawn, you need to dim your vars first!
And X is of course your NameOfEditfield.Text

13

says my string does not exist

[code] If ComboBox1.text = “AXS- Access Promos” then
if (TextField_CD.Text) < “10” Then
dim mystring as string = “0”
else
dim mystring as string = “00”
end if

MsgBox  field + mystring + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text

End If[/code]

14

Quite good Shawn, I see you are new to Xojo so welcome aboard first.
May I would suggest you to take a look into this superb eBook?

15

[code] If ComboBox1.text = “AXS- Access Promos” then

if (TextField_CD.Text) < "10" Then
  //this works
  MsgBox "00 " + TextField_CD.Text
end if

//this does not, says s does not exits
MsgBox  field + s + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text

End If[/code]

16

thanks tomas, already got it, and many other too, need to read them all.

17

got it to work

[code] If ComboBox1.text = “AXS- Access Promos” then

if (TextField_CD.Text) < "10" Then
  //this works
  MsgBox  field + "00" + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text
else
  MsgBox  field + "0" + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text
end if

End If[/code]

18

For your learning…

code < “10” Then
dim mystring as string = “0”
else[/code]
The reason that code did not work is because you dimmed your variable inside the conditional. If…then…else
Once that conditional finished, your var. ceased to exist.
Dim your var. before the conditional then just do assignment within the cond.

19

Obviously you really need to read the first one
Introduction to Programming with Xojo

it will save you a world of confusion.

20

if CD=1 it works I get 001
if CD=2-9 it DOES NOT WORK, I get 02,03,04 instead of 002,003,004
if CD=10 it works I get 010,011,012

[code] If ComboBox1.text = “AXS- Access Promos” then

if "0">(TextField_CD.Text)  and (TextField_CD.Text) < "10" Then
  dim mystring as string = "00"
  MsgBox field + mystring + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text
  
else
  dim mystring as string = "0"
  MsgBox  field + mystring + TextField_CD.Text + Chr(13) + field + "_" +  TextField_CD.Text + "_" + TextField_CUT.Text
  
end if

End If[/code]