Fast way to check divisible by 2

General
1

What is the quickest way to check whether a number is divisible by 2

2

Someone started and deleted a thread. For those looking for the answer:
https://documentation.xojo.com/api/math/mod.html

3

check and see if the lowest bit is set

if (number and &b1) > 0
     if it is its an odd number
else
     if it isnt its even & therefor divisible by 2
end if

dunno if this is quicker than mod but it should be

4

I tested, they are about the same.

5 
if ( number mod 2 ) = 0 then
  // it's even
else
  // it's odd
end if