EndOfLine not working on a Mac

General
1

I used a simple string, e.g. string = “some text” + EndOfLine + “some text”
but it did no carriage return.
EndOfLine.Macintosh does not work either.
where is the problem ?

Johann

2

Maybe your problem is related to this change:

3

EndOfLine.Unix does not work either.

4

How are you determining that EndOfLine is not working? What is your code?

It certainly appears to be working here. This code displays the text on two lines in a TextArea, for example:

TextArea1.Text = "Hello" + EndOfLine + "World"
5

[quote=81248:@Johann JFK]I used a simple string, e.g. string = “some text” + EndOfLine + “some text”
but it did no carriage return.
EndOfLine.Macintosh does not work either.[/quote]

Both versions do work in that they create two lines of text, i.e. they do insert a valid end-of-line character. That character isn’t carriage return (ASCII 13), though, as the end-of-line character is linefeed (ASCII 10).

6

I put it in a MessageDialog and it does not do a carriage return.

7

That’s not indicative of it not working
MessageDialog may actually NOT support multiline messages

8

MsgBox may be a better choice here.

9

What platform? On a Mac, the code below gives me two lines:

  dim dlg as new MessageDialog
  dlg.Message = "this" + EndOfLine + "that"
  call dlg.ShowModal
10

and on OSX this gives me 3 lines

msgbox "line 1"+EndOfLine+"line2"+EndOfLine+"line3"
11

With the same code as Kem :

12

I’m passing the concatenated string to a function which displays a MessageDialog with this message,
this does not display the message in different lines, maybe I have to restructure my function.

thanks to all

13

I did some testing.
it works with static text strings but as soon as I add a variable to the string, the EndOfLine does not work.

14

post an example

  dim a as string="line1"
  dim b as string="line2"
  dim c as string="Line3"
  msgbox a+EndOfLine+b+EndOfLine+c

still works as advertised…

are you seeing a black diamond with a ? in it?
If so, the encoding of your passed string is not correct.

15

yes, I get a black diamond with a ?,
how can I correct it ?

16

Post your actual code please.

17

this is my code:

dlg.Message = “Delete selected customer type ?” + EndOfLine + EndOfLine + _
"CustomerType: " + invThis.type + " " + EndOfLine + _
"Customer name: "
b = dlg.ShowModalWithin(self)

the variables invThis.type is a string.

18

Try this:

dim msg as string =  "Delete selected customer type ?" + EndOfLine + EndOfLine + _
"CustomerType: " + invThis.type + " " + EndOfLine + _
"Customer name: " 
msg = msg.ConvertEncoding( Encodings.UTF8 )
dlg.Message = msg
…

If that doesn’t work, change “ConvertEncoding” to “DefineEncoding” and try again.

19

Try

dlg.Message = “Delete selected customer type ?” + EndOfLine + EndOfLine + _
"CustomerType: " + invThis.type + " " + EndOfLine + _
"Customer name: "
break
b = dlg.ShowModalWithin(self)

When the program STOPS on the BRAK statement look at invThis.Type in the debugger
I suspect it has a nil encoding & that’s where part of your problem comes from - its “bytes” not a string with a known encoding

20

the variable is ok, I was debugging it.

where can I change the “ConvertEncoding” to “DefineEncoding” ?