Xcode -> Swift -> Xojo

Off-Topic
1

Xcode 4:
NSArray *names = [[NSArray alloc] initWithObjects: @“Tom”, @“Dick”, @“Harry”, nil];

Xcode 5:
NSArray *names = @[@“Tom”, @“Dick”, @“Harry”];

Swift:
let names = [“Tom”, “Dick”, “Harry”]

Xojo:
names = (“Tom”, “Dick”, “Harry”)

[ok, cheated a bit, left the dim statement out]

2

actually, I believe in Swift, you still need the @ signs, so this is what it should be.

let names = [@“Tom”, @"!@#$%", @“Harry”]

3

Cheated a bit?

4

In Xojo, you need the Array keyword.

I don’t think you need “@” in Swift. Can anyone confirm one way or the other?

5

Xojo:

Dim names() As String = Array(“a”, “b”, “c”)

Swift:

var names = [“a”, “b”, “c”]

6

You most certainly don’t need any @ symbols in Swift. It was a way to separate the Objective-C part of the C code. Swift has no such baggage.

7

var names = [“a”, “b”, “c”]

is the short way, using type inference, for the explicit:

var names: String[] = [“a”, “b”, “c”]

8

I stand corrected.

9

Objective-C string concatenation:

NSString *myString = @"Stop"; NSString *myString2 = [myString stringByAppendingString:@" all Off-Topic threads"];

Swift string concatenation:

var myString = "Stop" var myString2 = myString + " all Off-Topic threads"

Simple.

10

we could certainly rewrite the xojo language and use [] () ; and all those C idioms

BUT it’d be “xojo++” or “xojo swift” or something else

given the language we have and the spec it has today I’d say the chance is close to 0

11

What is Swift’s equivalent for Variant? Because I’m pretty sure I tried this and it worked:

var n = [1, "2", 3]
12

[quote=96909:@Kem Tekinay]

var n = [1, "2", 3] [/quote]
That wouldn’t work, you can’t mix types like that in a Swift array.

You should check out Swift enums though - wow!

13

If you have an hour, I highly recommend checking out the Introduction to Swift session video. https://developer.apple.com/videos/wwdc/2014/

(I think that should be available if you don’t have a paid-up Developer account, but I’m not sure cos, well, I do)

14

[quote=96911:@Gavin Smith]That wouldn’t work, you can’t mix types like that in a Swift array.

You should check out Swift enums though - wow![/quote]

I just tried this code and it ran:

var n = ["a", 2, "c" ]
println( n )

So what did I end up with in n?

15

I think there is a type called “Any”

16

[quote=96921:@Kem Tekinay]I just tried this code and it ran:

var n = ["a", 2, "c" ]
println( n )

So what did I end up with in n?[/quote]
It ran? It doesn’t run here. What did it print out?

17 
(
    a,
    2,
    c
)
18

Perhaps it will spit stuff out in a Playground but it’s not a valid array as they require only one type. This is what I see in my Xcode Playground.

19

var v = Any
v.append(42)
v.append(3.14)
v.append(“hello”)
v.append((3.0, 5.0))

20

I started a new CLI project to test.