textVariant = stringVariant throws IDE exception when running

dim t as text = "test" dim s as string = "test" dim v1 as Variant = t dim v2 as Variant = s if v1 = v2 then break else break end

I’m thinking this is related to why classic dictionary lookups with the new Text datatype also doesn’t work.

<https://xojo.com/issue/39700>

If anyone wants to know how to get around this bug do this:

if v.Type = variant.TypeText then v = v.StringValue if v2.Type = variant.TypeText then v2= v2.StringValue