I need to split this string into an array which I am happy with:
[code]Dim theShell As New Shell
Dim theVolumesData(-1) As String
theShell.Execute "df -h " + f.NativePath // RETURNS 0 /dev/disk0s2 931Gi 88Gi 842Gi 10% 23229661 220751081 10% /
theVolumesData = Split(ReplaceLineEndings(theShell.ReadAll, EndOfLine), EndOfLine)
Dim anArray(-1) as String
anArray=Split(str(theVolumesData(1))," ")[/code]
However, obviously this is splitting via a space, Is there any way of wildcarding the space because between each of the elements in the string there will always be a unknown amount of spaces due to the fact it is from shell.
Get the MacOSLib package and take a look at the DiskUtil module within it. That will give you an alternate, object-oriented way to get disk information.
Get my M_String module and take a look at SplitByRegEX. (The pattern \\x20+ would do it.)
Perhaps easier, using Squeeze within M_String to reduce the multiple spaces to one each, then use ordinary Split.
Use a regular expression. The pattern ([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) +([^ ]+) + will break out each piece of data into its own subgroup.
Do it exactly as you’re doing it, but then run through the array, delete the empty elements, and trim the rest.
[quote=93097:@Steven Church]However, obviously this is splitting via a space, Is there any way of wildcarding the space because between each of the elements in the string there will always be a unknown amount of spaces due to the fact it is from shell.
[/quote]
Do a Result = ReplaceAll(Result," "," ") three or four times in a raw to reduce spaces to a single space, then split ?
Yes. I could have just put in a space, but I like that form (especially on the forum) for clarity.
FYI, in regex, you can specify a code point as either \xNN or \x{NNNN}. The latter form will work for any number of hex digits so \x{a}, for example, would match a linefeed.
[quote=93191:@Kem Tekinay]Yes. I could have just put in a space, but I like that form (especially on the forum) for clarity.
FYI, in regex, you can specify a code point as either \xNN or \x{NNNN}. The latter form will work for any number of hex digits so \x{a}, for example, would match a linefeed.[/quote]
I have learned a tiny bit of RegEx today. Thank you
[quote=93183:@Kem Tekinay]Just to close the loop, this code will squeeze the spaces if you want to keep it all within Xojo code:
rx.SearchPattern = "\\x20{2,}"
[/quote]
Interesting. If I understand right, your search pattern looks for 2 spaces and replaces that by one. ReplaceAll has an issue when it encounters 3 spaces : it leaves two. So it must be run twice. Your code replaces three spaces by one in one pass.
That pattern looks for two or more spaces. If you follow a token with a {x} structure, that says, “repeating x times”. You can do a range with {x,y}, but you can also leave it open-ended by leaving off y, as I did above.
HOWEVER, due to a flaw in the native RegEx implementation, that pattern may take forever with the native RegEx class against long strings, so your way could be much faster.
With the MBS version (RegExMBS), there is no contest. In my M_String test project, where you supply a character set to squeeze, looping over a long string takes almost six seconds. With RegExMBS, it takes about 0.6 seconds.
