Help with parser by CharcoalDesign

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Hey there,
Please could somebody guide me as how I can make the parsing ‘suceed’ without having to print a value. It seems that it requires the print function to be called and every code pathway needs to filled. How can I prevent it from looking out for this? I want to be able to have a successful path with something like this:

if "" = "" then

As long as the execution of the code should work fine if it was to be compiled, I don’t care if the program does not have all code pathways filled.