Convert Binary-Integer in String to real Integer

5 months ago
Henrik S
Nov 13
Hello everyone,
how to convert a data type packed in a string back to its original type?
For example
The first 8 bytes of a string contain a UInt32 number:
B90D 0000 0000 0000 [Binary]
How can I make 3513 [Dec] out of it?
Here's what I tried to do:
```
Dim mbc As MemoryBlock = StringRepresentationOfInteger
Dim mb As New Xojo.Core.MutableMemoryBlock( mbc, mbc.Size )
Dim tmp As UInt32
tmp = mb.UInt32Value(0)
```
It works, but is that the best way?

Answered by Norman P
See post in context

That looks more like an int64 to me (since every hex digit is 4 bits)
other than that endianess _may_ be relevant but this is a reasonable way to do this
Norman P
Nov 13 Xojo Inc Answer

That looks more like an int64 to me (since every hex digit is 4 bits)
other than that endianess _may_ be relevant but this is a reasonable way to do this
Christian S
Nov 13 Pre-Release Testers, Xojo Pro, XDC Speakers Germany

the conversion from old memory block to new memory block is an extra unnecessary step.
Henrik S
Nov 13

Edited 5 months ago
@Norman P That looks more like an int64 to me (since every hex digit is 4 bits)
other than that endianess _may_ be relevant but this is a reasonable way to do this
Your're right. It's UInt64, my fault.
@ChristianSchmitz the conversion from old memory block to new memory block is an extra unnecessary step.
You're right. This works too:
```
Dim mbc As MemoryBlock = StringRepresentationOfInteger
Dim tmp As UInt64
tmp = mbc.UInt64Value(0)
```